and运算符就是所谓的布尔运算符,连接两个布尔值,并且在两者都为真时返回真,否则 返回假,or not 可以随意结合真值
短路逻辑 short-circuit logic 惰性求值 lazy evaluation raw_input 返回值为真 断言,条件后可以添加字符串,用来解释断言x = 1Yes = input('Are you readly?')if Yes.lower() == 'yes': while x <= 'yes': print(x) x += 1缩进对Python 太重要了!
name = ''
while not name: name = input('Please enter your name: ')print('Hello,%s!' % name)Name = input('Please input you name: ')
name = Namewhile not name or name.isspace(): #while not name.strip() or while not name or name.isspace() # name = input('Please enter your name: ')print('Hello,%s!'% name)# sequence list words = ['this','is','an','ex','parrot']
#for word in words:# print(word)"""numbers = [0,1,2,3,4,5,6,7,8,9]for number in numbers: print(number)"""'''d = {'x':1,'y':2,'z':3}for key in d: print(key,'corresponds to',d[key])#multiline commit for python#one line commeit for Python''''''d = {'x':1,'y':2,'z':3}print(d[key])#for key in d:# print(d[value])''''''d = {'x':1,'y':2,'z':3}for key,value in d.items(): print(key,'correspond to',value) '''"""names = ['anne','beth','george','damon']ages = [12,45,32,102]for i in range(len(names)): print(names[i],'is',ages[i],'years old')for string in strings: if 'xxx' in string: index = strings.index(string) # Search for the string in the list of strings strings[index] = '[censored]'"""for string in srings: if 'xxx' in string: index = strings.index(string) strings[index] = '[censored]'
posted on 2015-12-28 18:17 阅读( ...) 评论( ...)